Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 180: 108

Answer

$1~cm/min$

Work Step by Step

Given $\frac{dV}{dt}=1200cm^3/min$, at $a=20cm$, with $V=a^3$, we have $\frac{dV}{dt}=3a^2\frac{da}{dt}$ Thus $1200=3(20)^2\frac{da}{dt}$, which gives $\frac{da}{dt}=1cm/min$
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