Answer
$$\ \int \frac{\cosh x}{\sinh x} dx
=\ln |\sinh x| +c.$$
Work Step by Step
Let $ u=\sinh x $, then $ du=\cosh x dx $ and hence
$$\ \int \frac{\cosh x}{\sinh x} dx =\int \frac{du}{u} = \ln |u|+c
=\ln |\sinh x| +c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.9 Hyperbolic Functions - Exercises - Page 384: 44
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