Answer
$$\int \sinh (x+1) dx= \cosh (x+1)+c.$$
Work Step by Step
Let $ u=x+1$, then $ du=dx $ and hence
$$\int \sinh (x+1) dx= \int \sinh udu = \cosh u+c
\\= \cosh (x+1)+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.9 Hyperbolic Functions - Exercises - Page 384: 36
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