Answer
$$ y'= 2x \cosh (x^2)$$
Work Step by Step
Since $ y=\sinh (x^2)$, then using the chain rule, the derivative $ y'$ is given by
$$ y'= \cosh (x^2) (x^2)'=2x \cosh (x^2).$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.9 Hyperbolic Functions - Exercises - Page 384: 10
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