Answer
$0.0073$%
Work Step by Step
Let $f(x) = e^{x}, a=0$
$f(a) = f(0) = e^{0} = 1$
$f'(x) = e^{x}$
$f'(a) = f'(0) = 1$
$L(x) = f'(a)(x-a)+f(a)$
$L(x) = 1(x-0)+1$ = $x+1$
$L(-0.012) = -0.012+1 = 0.988$
Percentage error = $|\frac{e^{-0.012}-0.988}{e^{-0.012}}|\times100$% = $0.0073$%