Answer
$±0.45$ $atmospheres$
Work Step by Step
$PV$ = $24$
$P(V)$ = $24V^{-1}$
$P'(V)$ = $-24V^{-2}$
$P'(V)$ = $\frac{ΔP}{ΔV}$
$ΔP$ = $P'(V)ΔV$
$ΔP$ = $-24V^{-2}ΔV$
$ΔP$ = $-24(4)^{-2}(±0.3)$
$ΔP$ = $±0.45$ $atmospheres$
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