Answer
$$y=C \sec t$$
Work Step by Step
\begin{align*}
\frac{dy}{dt}&= y\tan y\\
\int \frac{1}{y} d y&=\int \tan t d t\\
\ln y&=\ln (\sec t)+\ln C\\
y&=C \sec t
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 10 - Introduction to Differential Equations - 10.1 Solving Differential Equations - Exercises - Page 505: 29
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