Answer
$\frac{\pi}{6}$
Work Step by Step
$$ V = \pi \int_{0}^{1}[{(\sqrt{y})}^2-y^2]dy$$
$$ V = \pi \int_{0}^{1}[y-y^2]dy$$
$$ V = \pi [\frac{y^2}{2}-\frac{y^3}{3}]_{0}^{1}$$
$$ V = \pi[\frac{1}{6}]=\frac{\pi}{6}$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 7 - Applications of Integration - 7.2 Exercises - Page 454: 47
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
