Answer
$\frac{2\pi}{3}$
Work Step by Step
Setup the integration using disk method about the x-axis
$\pi \int_1^3(\frac{1}{x})^2dx$
$\pi \int_1^3 (\frac{1}{x^2})dx$
$\pi[-\frac{1}{x}]_1^3$
$\pi(-\frac{1}{3}+1)$
$\frac{2\pi}{3}$
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