Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises - Page 454: 37

Answer

$$V \approx 1.9686$$

Work Step by Step

$$\eqalign{ & y = {e^{ - {x^2}}},{\text{ }}y = 0,{\text{ }}x = 0,{\text{ }}x = 2 \cr & V = \pi \int_a^b {{{\left[ {R\left( x \right)} \right]}^2}} dx \cr & {\text{Let }}R\left( x \right) = {e^{ - {x^2}}} \cr & {\text{So}},{\text{ the volume of the solid of revolution is}} \cr & V = \pi \int_0^2 {{{\left( {{e^{ - {x^2}}}} \right)}^2}} dx \cr & V = \pi \int_0^2 {{e^{ - 2{x^2}}}} dx \cr & {\text{Integrating by using the integration capability of a scientific }} \cr & {\text{calculator, we obtain}} \cr & V \approx \pi \left( {0.62661} \right) \cr & V \approx 1.9686 \cr} $$
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