Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises - Page 454: 43

Answer

$\frac{2\pi}{15}$

Work Step by Step

$$V = \pi \int_{0}^{1}(x^2-{(x^2)}^2)dx$$ $$V = \pi\int_{0}^{1}(x^2-x^4)dx$$ $$V = \pi\int_{0}^{1}(\frac{x^3}{3}-\frac{x^5}{5}) dx $$ Solving, we get $$ V = \frac{2\pi}{15}$$
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