Answer
$F^{\prime}(x)=0$
Work Step by Step
$F(x)=\displaystyle \int_{-x}^{x}t^{3}dt=[\frac{1}{4}t^{4}]_{-x}^{x}$
$= \displaystyle \frac{1}{4}[x^{4}-(-x)^{4}]$
$F(x)=0$
$F^{\prime}(x)=0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.4 Exercises - Page 290: 88
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