Answer
$F(x)=2x^2-7x$
$F(2)=-6$
$F(5)=15$
$F(8)=72$
Work Step by Step
Find F then evaluate at x=2,5,8
$\int^x_0 (4t-7)dt$
$[2t^2 -7t]^x_0$
$2x^2-7x-0$
Evaluate when x=2,5,8
$(8-14)=-6$
$(50-35)=15$
$(128-56)=72$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.4 Exercises - Page 290: 67
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