Answer
$$\frac{A}{{x - 3}} + \frac{B}{{x + 4}}$$
Work Step by Step
$$\eqalign{
& \frac{{3x - 1}}{{\left( {x - 3} \right)\left( {x + 4} \right)}} \cr
& {\text{The factors in the denominator }}x - 3{\text{ and }}x + 4{\text{ are linear}}{\text{, }} \cr
& {\text{so the numerator for each factor is a constant}}{\text{.}} \cr
& {\text{The partial fraction decomposition is in the form:}} \cr
& \frac{{3x - 1}}{{\left( {x - 3} \right)\left( {x + 4} \right)}} = \frac{A}{{x - 3}} + \frac{B}{{x + 4}} \cr} $$