Answer
$ n=\frac{7}{4} $ or $n=-\frac{7}{4} $.
Work Step by Step
By factorization, we have $$16n^2-49=(4n+7)(4n-7)=0.$$ Then we have $$(4n-7 ) =0, \quad \text{or} \quad (4n+7)=0$$
That is,
$ n=\frac{7}{4} $ or $n=-\frac{7}{4} $.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 8
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