Answer
$ n=0 $ or $n=\frac{5}{2}$.
Work Step by Step
By factorization, we have
$$6n^2-15n=3n(2n-5) =0.$$
Then we have
$$3n =0, \quad \text{or} \quad (2n-5)=0$$
that is $ n= 0$ or $n=\frac{5}{2}$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 18
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