Answer
$c=-8$ or $c=2$.
Work Step by Step
By factorization, we have $$c^2 +6c-16=(c+8)(c-2)=0.$$ Then we have $$(c+8) =0, \quad \text{or} \quad (c-2)=0$$ that is,
$c=-8$ or $c=2$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 21
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