Answer
$x=-\frac{2}{5}$ or $x=-\frac{5}{2}$.
Work Step by Step
By factorization, we have
$$10x^2 +29 x+10=(5x+2)(2x+5)=0.$$
Then we have $$(5x+2) =0, \quad \text{or} \quad (2x+5)=0$$
that is
$x=-\frac{2}{5}$ or $x=-\frac{5}{2}$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 23
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