Answer
$ n=4 $ or $n=-4$.
Work Step by Step
By factorization, we have
$$4n^2-64=(2n+8)(2n-8)=0.$$
Then we have
$$(2n-8 ) =0, \quad \text{or} \quad (2n+8)=0$$
that is $ n=4 $ or $n=-4$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 10
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