Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 30

Answer

Length = $12$ ft Width = $7$ ft

Work Step by Step

We know that the 2 sides of the rectangle are $(x+5)$ and $x$, and the area of the rectangle is $84$ $ft^{2}$. The formula for finding the area of a rectangle is; Length $\times$ width. We know that; Length = $(x+5)$ Width = $x$ So, we can substitute these values into the formula and form a quadratic equation! Area = Length x Width $84 = (x+5)\times x$ $84 = x^{2} +5x$ Subtract 84 from both sides of the equation. $x^{2} +5x-84=0$ Now, we have a quadratic equation. We can solve this equation to find the solution for $x$ by factorizing. $x^{2} +5x-84=0$ $x^{2} +12x-7x-84=0$ $x(x+12)-7(x+12)=0$ $(x-7)(x+12)=0$ Now, we can get the roots of the equation by making each bracket equal to 0. $(x-7)=0$ or $(x+12)=0$ $x=7$ or $x=-12$ We cross out $-12$, as a rectangle cannot have a negative value as one of its sides, so $x$=7. Length= $(7)+5$ = $12$ ft Width = $7$ ft
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