Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 32

Answer

Length = $24$ ft Width = $15$ ft

Work Step by Step

First, we can illustrate the problem given in the question for a better understanding, as seen below. We know that; Length = $(x+9)$ Width = $x$ Area = $360 ft^2$ The formula for the area of a rectangle is; Length $\times$ Width. We can use the values we have and substitute them into this formula to form a quadratic equation. Area = Length $\times$ Width 360 = $(x+9) \times x$ $360 = x^2+9x$ (Subtract 360 from the equation to make it equal 0) $x^2+9x-360=0$ We now have our quadratic equation, which we can solve by factoring! $x^2+9x-360=0$ $x^2+24x-15x-360=0$ $x(x+24)-15(x+24)=0$ $(x-15)(x+24)=0$ To find the solutions for $x$, we can make both brackets = 0. $(x-15)=0$ or $(x+24)=0$ $x=15$ or $x=-24$ We rule out $-24$, as $x$ cannot be a negative number in this case as it is the width of the rectangle, which cannot be lower than $0$. So, $x=15$ Length = $(15)+9$ =$24$ ft Width = $15$ ft
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