Answer
$x=12$ or $x=-9$.
Work Step by Step
By factorization, we have
$$x^2 -3 x-108=(x+9)(x-12)=0.$$ Then we have $$(x-12) =0, \quad \text{or} \quad (x+9)=0$$ that is,
$x=12$ or $x=-9$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 19
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