Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.1 - Solving Quadratic Equations by Factoring - Exercise - Page 364: 13

Answer

$y=7$ or $y=-3$.

Work Step by Step

By factorization, we have $$y^2 -4y-21=(y-7)(y+3)=0.$$ Then we have $$(y-7) =0, \quad \text{or} \quad (y+3)=0$$ that is $y=7$ or $y=-3$.
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