Answer
$(xy-4)(x^2y^2+4xy+16)$
Work Step by Step
The given binomial can be written as:
$(xy)^3-4^3$
The binomial above is a difference of two cubes.
RECALL:
A difference of two cubes can be factored using the formula:
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Use the formula above to factor the sum of two cubes with $a=xy$ and $b=4$ to obtain:
$=(xy-4)[(xy)^2+xy(4) + 4^2]
\\=(xy-4)(x^2y^2+4xy+16)$
