Answer
$2x(3x-1)(3x+1)$
Work Step by Step
Factor out $2x$ to obtain:
$=2x(9x^2-1)$
Write $9x^2$ as $(3x)^2$ to obtain:
$=2x[(3x)^2-1]$
The binomial is a difference of two squares.
RECALL:
A difference of two squares can be factored using the formula:
$a^2-b^2=(a-b)(a+b)$
Factor the difference of two squares using the formula above with $a=3x$ and $b=1$ to obtain:
$=2x(3x-1)(3x+1)$