Answer
$(x-1)(x+1)(x^2+1)$
Work Step by Step
RECALL:
A difference of two square can be factored using the formula
$a^2-b^2=(a-b)(a+b)$
The given binomial can be written as:
$=(x^2)^2-1^2$
The binomial above is a difference of two squares.
Factor the difference of two squares using the formula above with $a=x^2$ and $b=1$ to obtain:
$=(x^2-1)(x^2+1)
\\=(x^2-1^2)(x^2+1)$
The first factor is a difference of two squares. Factor using the formula above with $a=x$ and $b=1$ to obtain:
$=(x-1)(x+1)(x^2+1)$
