Answer
$(3y-1)(9y^2+3y+1)$
Work Step by Step
The given binomial can be written as:
$(3y)^3-1^3$
The binomial above is a difference of two cubes.
RECALL:
A difference of two cubes can be factored using the formula:
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Use the formula above to factor the sum of two cubes with $a=3y$ and $b=1$ to obtain:
$=(3y-1)[(3y)^2+3y(1) + 1^2]
\\=(3y-1)(9y^2+3y+1)$
