Answer
$(2x-3)(2x+3)(4x^2+9)$
Work Step by Step
RECALL:
A difference of two square can be factored using the formula
$a^2-b^2=(a-b)(a+b)$
The given binomial can be written as:
$=(4x^2)^2-9^2$
The binomial above is a difference of two squares.
Factor the difference of two squares using the formula above with $a=4x^2$ and $b=9$ to obtain:
$=(4x^2-9)(4x^2+9)$
The first binomial factor can be written as:
$=[(2x)^2-3^2](4x^2+9)$
The first binomial factor is a difference of two squares. Factor using the formula above with $a=2x$ and $b=3$ to obtain:
$=(2x-3)(2x+3)(4x^2+9)$
