Answer
$(x-3)(x^2+3x+9)$
Work Step by Step
The given binomial can be written as:
$x^3-3^3$
The binomial above is a difference of two cubes.
RECALL:
A difference of two cubes can be factored using the formula:
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Use the formula above to factor the sum of two cubes with $a=x$ and $b=3$ to obtain:
$=(x-3)(x^2+x(3) + 3^2)
\\=(x-3)(x^2+3x+9)$