Answer
$-6y(3y-1)(3y+1)$
Work Step by Step
Factor out $-6y$ to obtain:
$=-6y(9y^2-1)$
Write $9y^2$ as $(3y)^2$ to obtain:
$=-6y[(3y)^2-1]$
The binomial is a difference of two squares.
RECALL:
A difference of two squares can be factored using the formula:
$a^2-b^2=(a-b)(a+b)$
Factor the difference of two squares using the formula above with $a=3y$ and $b=1$ to obtain:
$=-6y(3y-1)(3y+1)$
