Answer
$(3x-1)(3x+1)(9x^2+1)$
Work Step by Step
RECALL:
A difference of two square can be factored using the formula
$a^2-b^2=(a-b)(a+b)$
The given binomial can be written as:
$=(9x^2)^2-1^2$
The binomial above is a difference of two squares.
Factor the difference of two squares using the formula above with $a=9x^2$ and $b=1$ to obtain:
$=(9x^2-1)(9x^2+1)$
The first binomial factor can be written as:
$=[(3x)^2-1^2](9x^2+1)$
The first binomial factor is a difference of two squares. Factor using the formula above with $a=3x$ and $b=1$ to obtain:
$=(3x-1)(3x+1)(9x^2+1)$
