Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 126

Answer

$x=\dfrac{17}{3}$

Work Step by Step

Since $\log_b x=y$ is equivalent to $b^y=x$, then, \begin{array}{l} \log_4 (3x-1)=2\\\\ 3x-1=4^2\\\\ 3x-1=16\\\\ 3x=17\\\\ x=\dfrac{17}{3} .\end{array}
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