Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 118

Answer

$x\approx2.82$

Work Step by Step

Taking the logarithm of both sides, the value of $x$ in the expression $ 10^{0.3x}=7 $ is, \begin{array}{l} \log10^{0.3x}=\log7\\ 0.3x(\log10)=\log7\\ 0.3x(1)=\log7\\ 0.3x=\log7\\ 3x=10\log7\\ x=\dfrac{10\log7}{3}\\ x\approx2.82 .\end{array}
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