Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 110

Answer

$x=9$

Work Step by Step

Using properties of logarithms, then, \begin{array}{l} \log_3 (x^2-8x)=2\\ x^2-8x=3^2\\ x^2-8x=9\\ x^2-8x-9=0\\ (x-9)(x+1)=0\\ x=\{-1,9\} .\end{array} Since the domain of the logarithmic function is the set of all positive numbers, then $ x=9 $.
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