Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 105

Answer

$x=\dfrac{25}{2}$

Work Step by Step

Using properties of logarithms, then, \begin{array}{l} \log_52+\log_5x=2\\\\ \log_5(2x)=2\\\\ 5^2=2x\\\\ 2x=25\\\\ x=\dfrac{25}{2} .\end{array}
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