Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 106

Answer

$x=\dfrac{9}{10}$

Work Step by Step

Using properties of logarithms, then, \begin{array}{l} \log_3x+\log_310=2\\\\ \log_3(10x)=2\\\\ 3^2=10x\\\\ 10x=9\\\\ x=\dfrac{9}{10} .\end{array}
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