Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 104

Answer

$x= \frac{log (2/3)}{log 4}-5$ $x=-5.2925$

Work Step by Step

$4^{x+5} =2/3$ $log (4^{x+5}) =log (2/3)$ $(x+5) log 4 = log (2/3)$ $(x+5) log 4/log 4 = log (2/3)/log 4$ $x+5 = log (2/3) /log 4$ $x+5-5 = log (2/3) /log 4 -5$ $x= log (2/3) /log 4 -5$ $x= log (2/3) /log 4 -5$ $x= -.17609 /.60206 -5$ $x=-.29248 -5$ $x=-5.2925$
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