Answer
$x\approx0.69$
Work Step by Step
Taking the natural logarithm of both sides, the value of $x$ in the expression $
e^x=2
$ is,
\begin{array}{l}
\ln e^x=\ln2\\
x\ln e=\ln2\\
x(1)=\ln2\\
x=\ln2\\
x\approx0.69
.\end{array}
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