Answer
$ \displaystyle \frac{5m-7}{(m+1)(m-5)}$
Work Step by Step
To add, expand each algebraic fraction to the common denominator.
LCD=$(m+1)(m-5)$
$\displaystyle \frac{2}{m+1}+\frac{3}{m-5}=\frac{2}{m+1}\cdot\frac{m-5}{m-5}+\frac{3}{m-5}\cdot\frac{m+1}{m+1}$
$=\displaystyle \frac{2m-10+3m+3}{(m+1)(m-5)}$
$=\displaystyle \frac{5m-7}{(m+1)(m-5)}$