Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 826: 71

Answer

$ \displaystyle \frac{5m-7}{(m+1)(m-5)}$

Work Step by Step

To add, expand each algebraic fraction to the common denominator. LCD=$(m+1)(m-5)$ $\displaystyle \frac{2}{m+1}+\frac{3}{m-5}=\frac{2}{m+1}\cdot\frac{m-5}{m-5}+\frac{3}{m-5}\cdot\frac{m+1}{m+1}$ $=\displaystyle \frac{2m-10+3m+3}{(m+1)(m-5)}$ $=\displaystyle \frac{5m-7}{(m+1)(m-5)}$
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