Answer
$f(x)=x^{4},\ \quad g(x)=3x-5$
Work Step by Step
$h(x)$ equals the 4th power of (the difference of 3x and 5)
So if we define $g(x)$ as (the difference of 3x and 5)
and $f(x)$ as the (4th power of x)
then $h(x)=f[g(x)]=(f\circ g)(x).$
$f(x)=x^{4},\ \quad g(x)=3x-5$