Answer
$a.\quad(f\circ g)(1) = 9$
$b.\quad(g\circ f)(1) = 3$
$c.\quad (f\circ g)(x) = 10-\sqrt{x}$
$d.\quad (g\circ f)(x) = \sqrt{10-x}$
Work Step by Step
$(f\circ g)(x)=f[g(x)]=10-g(x)$
$= 10-\sqrt{x} \qquad ... \quad(c)$
$(f\circ g)(1)=10-\sqrt{1}=9 \qquad ... \quad(a)$
$(g\circ f)(x)=g[f(x)]=\sqrt{f(x)}$
$= \sqrt{10-x} \qquad ... \quad(d)$
$(g\circ f)(1)=\sqrt{10-1}=3 \qquad ... \quad(b)$