Answer
{$-2,7$}
Work Step by Step
Using the rules of factoring trinomials, we obtain:
$x^{2}-5x-14=0$
$x^{2}+2x-7x-14=0$
$x(x+2)-7(x+2)=0$
$(x+2)(x-7)=0$
$(x+2)=0$ and $(x-7)=0$
$x=-2$ and $x=7$
Therefore, the solution set is {$-2,7$}.
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 9
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