Answer
{$-\frac{3}{4},6$}
Work Step by Step
Using the rules of factoring trinomials and setting the factors equal to zero, we obtain:
$4y^{2}-21y-18=0$
$4y^{2}+3y-24y-18=0$
$y(4y+3)-6(4y+3)=0$
$(4y+3)(y-6)=0$
$(4y+3)=0$ and $(y-6)=0$
$y=-\frac{3}{4}$ and $y=6$
Therefore, the solution set is {$-\frac{3}{4},6$}.
