Answer
{$-6-\sqrt 5,-6+\sqrt 5$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
Step 1: $(x+6)^{2}=5$
Step 2: $x+6=\pm \sqrt {5}$
Step 3: $x+6=+ \sqrt {5}$ or $x+6=- \sqrt {5}$
Step 4: $x=-6+\sqrt 5$ or $x=-6-\sqrt 5$
The solution set is {$-6-\sqrt 5,-6+\sqrt 5$}.