Answer
{$-8, 2$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $(x+b)^{2}=a$ can be written as $x+b=\pm\sqrt a$, we obtain:
Step 1: $(x+3)^{2}=25$
Step 2: $x+3=\pm \sqrt {25}$
Step 3: $x+3=\pm 5$
Step 4: $x+3=5$ or $x+3=-5$
Step 5: $x=5-3$ or $x=-5-3$
Step 6: $x=2$ or $x=-8$
The solution set is {$-8, 2$}.
