Answer
{$-1, 5$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $(x-b)^{2}=a$ can be written as $x-b=\pm\sqrt a$, we obtain:
Step 1: $(x-2)^{2}=9$
Step 2: $x-2=\pm \sqrt 9$
Step 3: $x-2=\pm 3$
Step 4: $x-2=3$ or $x-2=-3$
Step 5: $x=3+2$ or $x=-3+2$
Step 6: $x=5$ or $x=-1$
The solution set is {$-1, 5$}.
