Answer
{$-\frac{2}{9},\frac{2}{9}$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
$x^{2}=\frac{4}{81}$
$x=\pm\sqrt {\frac{4}{81}}$
$x=\pm \frac{2}{9}$
The solution set is {$-\frac{2}{9},\frac{2}{9}$}.
