Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1 - Page 442: 24

{$-10,10$}

Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: $5x^{2}=500$ $x^{2}=\frac{500}{5}$ $x^{2}=100$ $x=\pm \sqrt {100}$ $x=\pm 10$ The solution set is {$-10,10$}.