Answer
{$-\frac{5}{3},\frac{5}{3}$}
Work Step by Step
Using Property 10.1, which states that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain:
$x^{2}=\frac{25}{9}$
$x=\pm\sqrt {\frac{25}{9}}$
$x=\pm \frac{5}{3}$
The solution set is {$-\frac{5}{3},\frac{5}{3}$}.
