Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 2 - Matrices and Systems of Linear Equations - 2.2 Matrix Algebra - Problems - Page 136: 17

Answer

See below

Work Step by Step

We have: $\sigma_1 \sigma_2=\begin{bmatrix} 0&1\\1&0 \end{bmatrix}\begin{bmatrix} 0 &-i\\i &0 \end{bmatrix}=\begin{bmatrix} i &0\\0 & -i \end{bmatrix}=i\sigma_3$ $\sigma_2 \sigma_3=\begin{bmatrix} 0 &-i\\i &0 \end{bmatrix}\begin{bmatrix} 1&0\\0&-1 \end{bmatrix}=\begin{bmatrix} 0 &i\\i & 0 \end{bmatrix}=i\sigma_1$ $\sigma_3\sigma_1=\begin{bmatrix} 1&0\\0 &-1 \end{bmatrix}\begin{bmatrix} 0&1\\1&0 \end{bmatrix}=\begin{bmatrix} 0 &1\\ -1 &0 \end{bmatrix}=i\sigma_2$
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